dengan menggunakan sifat sifat bilangan,sederhanakan soal soal berikut
tolong bantuu yaa plsss
tolong bantuu yaa plsss
Jawaban:
a. 3b²×3b⁵ =3b⁷
b. 11⁴:11² = 11²
c. 6⁷/6⁴ = 6³
d. (5-4)³ = (5-4)(5-4)(5-4)= 1
e. (p-r)² = (p-r)(p-r)(p-r)
f. 8²:2² = (2.2²)/2² = 2
[tex]a. \: 3 {b}^{2} \times 3 {b}^{5} = 3 \times 3 \times {b}^{2 + 5} = 9 {b}^{7} [/tex]
[tex] b. \: {11}^{4} \div {11}^{2} = {11}^{4 - 2} = {11}^{2} [/tex]
[tex]c. \: \frac{ {6}^{7} }{ {6}^{4} } = {6}^{7 - 4} = {6}^{3} [/tex]
[tex]d. \: {(5 - 4)}^{3} = {1}^{3} = 1[/tex]
[tex]e. \: {(p - r)}^{2} = {p}^{2} - 2pr + {r}^{2} [/tex]
[tex]f. \: {8}^{2} \div {2}^{2} = {( {2}^{3} )}^{2} \div {2}^{2} = {2}^{6} \div {2}^{2} = {2}^{6 - 2} = {2}^{4} [/tex]
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